When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + c = -7c + 4z - 8 for c in terms of z.
| -1\(\frac{5}{6}\)z - 1\(\frac{1}{6}\) | |
| -\(\frac{5}{8}\)z - \(\frac{1}{8}\) | |
| \(\frac{1}{3}\)z + \(\frac{2}{3}\) | |
| \(\frac{3}{11}\)z - \(\frac{8}{11}\) |