When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c - 4c = -4c - 3z + 4 for c in terms of z.
| 3\(\frac{1}{2}\)z + 1\(\frac{1}{2}\) | |
| \(\frac{1}{13}\)z + \(\frac{4}{13}\) | |
| -\(\frac{3}{5}\)z - \(\frac{3}{5}\) | |
| 13z + 3 |