ASVAB Math Knowledge Practice Test 665607 Results

Your Results Global Average
Questions 5 5
Correct 0 3.36
Score 0% 67%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

π r2h

4π r2

π r2h2

2(π r2) + 2π rh


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

What is the circumference of a circle with a diameter of 19?

71% Answer Correctly
19π
36π

Solution

The formula for circumference is circle diameter x π:

c = πd
c = 19π


3

If angle a = 36° and angle b = 55° what is the length of angle c?

71% Answer Correctly
126°
110°
109°
89°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 36° - 55° = 89°


4

What is 8a5 - 3a5?

73% Answer Correctly
5
5a5
24a5
a510

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a5 - 3a5 = 5a5


5

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
2\( \sqrt{2} \)
5\( \sqrt{2} \)
7\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)