When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c + 9c = 3c + 8z + 5 for c in terms of z.
| \(\frac{5}{16}\)z + \(\frac{1}{4}\) | |
| 2z - 6 | |
| \(\frac{1}{12}\)z - \(\frac{5}{12}\) | |
| \(\frac{2}{3}\)z + \(\frac{1}{2}\) |