ASVAB Math Knowledge Practice Test 666189 Results

Your Results Global Average
Questions 5 5
Correct 0 3.29
Score 0% 66%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

2(π r2) + 2π rh

π r2h2

4π r2

π r2h


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

If side a = 8, side b = 8, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{61} \)
\( \sqrt{128} \)
\( \sqrt{17} \)
\( \sqrt{113} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 82 + 82
c2 = 64 + 64
c2 = 128
c = \( \sqrt{128} \)


3

What is 3a3 + 5a3?

75% Answer Correctly
-2a6
-2
8a3
8

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a3 + 5a3 = 8a3


4

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
6\( \sqrt{2} \)
8\( \sqrt{2} \)
7\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)


5

Which of the following statements about math operations is incorrect?

70% Answer Correctly

you can multiply monomials that have different variables and different exponents

you can subtract monomials that have the same variable and the same exponent

you can add monomials that have the same variable and the same exponent

all of these statements are correct


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.