When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 5c = 2c - 9z - 2 for c in terms of z.
| 2\(\frac{1}{2}\)z + 1\(\frac{1}{2}\) | |
| -2z - \(\frac{2}{7}\) | |
| -1\(\frac{1}{5}\)z - \(\frac{1}{5}\) | |
| \(\frac{2}{3}\)z - 2\(\frac{2}{3}\) |