ASVAB Math Knowledge Practice Test 667547 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides

the area is length x width

all interior angles are right angles


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

deconstructing

squaring

factoring

normalizing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


3

What is 8a5 + 7a5?

76% Answer Correctly
1
15
a10
15a5

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a5 + 7a5 = 15a5


4

If side a = 3, side b = 3, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{18} \)
\( \sqrt{10} \)
\( \sqrt{45} \)
\( \sqrt{117} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 32 + 32
c2 = 9 + 9
c2 = 18
c = \( \sqrt{18} \)


5

Solve for z:
-4z + 8 = \( \frac{z}{2} \)

46% Answer Correctly
-1\(\frac{1}{35}\)
\(\frac{63}{80}\)
-\(\frac{7}{27}\)
1\(\frac{7}{9}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-4z + 8 = \( \frac{z}{2} \)
2 x (-4z + 8) = z
(2 x -4z) + (2 x 8) = z
-8z + 16 = z
-8z + 16 - z = 0
-8z - z = -16
-9z = -16
z = \( \frac{-16}{-9} \)
z = 1\(\frac{7}{9}\)