When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c - 3c = 6c - 9z + 1 for c in terms of z.
| -3z - 6 | |
| \(\frac{9}{11}\)z - \(\frac{7}{11}\) | |
| \(\frac{2}{5}\)z - \(\frac{1}{15}\) | |
| \(\frac{1}{5}\)z - 1\(\frac{1}{5}\) |