When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 4c = 4c + 5x + 1 for c in terms of x.
| x + \(\frac{1}{5}\) | |
| \(\frac{5}{16}\)x - \(\frac{3}{16}\) | |
| -\(\frac{1}{12}\)x - \(\frac{1}{12}\) | |
| -\(\frac{11}{16}\)x + \(\frac{1}{8}\) |