| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
The dimensions of this trapezoid are a = 6, b = 6, c = 9, d = 4, and h = 4. What is the area?
| 30 | |
| 20 | |
| 24 | |
| 9 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(6 + 4)(4)
a = ½(10)(4)
a = ½(40) = \( \frac{40}{2} \)
a = 20
If c = -9 and y = -9, what is the value of -3c(c - y)?
| 0 | |
| -200 | |
| 24 | |
| -168 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-3c(c - y)
-3(-9)(-9 + 9)
-3(-9)(0)
(27)(0)
0
Order the following types of angle from least number of degrees to most number of degrees.
right, acute, obtuse |
|
acute, obtuse, right |
|
acute, right, obtuse |
|
right, obtuse, acute |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
Solve for b:
-9b - 3 < 5 + 5b
| b < -1 | |
| b < -\(\frac{1}{2}\) | |
| b < \(\frac{8}{9}\) | |
| b < -\(\frac{4}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-9b - 3 < 5 + 5b
-9b < 5 + 5b + 3
-9b - 5b < 5 + 3
-14b < 8
b < \( \frac{8}{-14} \)
b < -\(\frac{4}{7}\)
If side a = 9, side b = 5, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{106} \) | |
| \( \sqrt{18} \) | |
| \( \sqrt{20} \) | |
| \( \sqrt{58} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 92 + 52
c2 = 81 + 25
c2 = 106
c = \( \sqrt{106} \)