| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.82 |
| Score | 0% | 56% |
Solve for b:
-2b - 3 < \( \frac{b}{-9} \)
| b < -1\(\frac{7}{17}\) | |
| b < -1\(\frac{10}{17}\) | |
| b < 2\(\frac{2}{5}\) | |
| b < -\(\frac{2}{13}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-2b - 3 < \( \frac{b}{-9} \)
-9 x (-2b - 3) < b
(-9 x -2b) + (-9 x -3) < b
18b + 27 < b
18b + 27 - b < 0
18b - b < -27
17b < -27
b < \( \frac{-27}{17} \)
b < -1\(\frac{10}{17}\)
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
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acute, obtuse |
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vertical, supplementary |
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obtuse, acute |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
The dimensions of this cylinder are height (h) = 5 and radius (r) = 5. What is the surface area?
| 100π | |
| 224π | |
| 132π | |
| 216π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(52) + 2π(5 x 5)
sa = 2π(25) + 2π(25)
sa = (2 x 25)π + (2 x 25)π
sa = 50π + 50π
sa = 100π
A cylinder with a radius (r) and a height (h) has a surface area of:
2(π r2) + 2π rh |
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π r2h |
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π r2h2 |
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4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
A(n) __________ is two expressions separated by an equal sign.
equation |
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formula |
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expression |
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problem |
An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.