When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8b - 3b = 4b + 4z + 3 for b in terms of z.
| -1\(\frac{1}{5}\)z - \(\frac{4}{5}\) | |
| -\(\frac{7}{12}\)z - \(\frac{1}{4}\) | |
| -\(\frac{1}{3}\)z - \(\frac{1}{4}\) | |
| -2\(\frac{1}{6}\)z + \(\frac{1}{2}\) |