When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 7c + 6c = 4c + 3z - 4 for c in terms of z.
| \(\frac{3}{5}\)z - \(\frac{4}{5}\) | |
| 12z + 7 | |
| -z - 1\(\frac{1}{3}\) | |
| -1\(\frac{5}{12}\)z - \(\frac{7}{12}\) |