When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 3c = 2c + 3y - 3 for c in terms of y.
| y - \(\frac{1}{2}\) | |
| 1\(\frac{3}{4}\)y - \(\frac{3}{8}\) | |
| \(\frac{3}{8}\)y - \(\frac{7}{8}\) | |
| 1\(\frac{1}{4}\)y + 1\(\frac{1}{2}\) |