ASVAB Math Knowledge Practice Test 670992

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a + 3a = 4a - 8y + 9 for a in terms of y.

\(\frac{1}{2}\)y + 3\(\frac{1}{2}\)
-14y - 4
1\(\frac{3}{4}\)y - \(\frac{5}{8}\)
-5\(\frac{1}{2}\)y + 4\(\frac{1}{2}\)