ASVAB Math Knowledge Practice Test 674394

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c + 5c = -c + 7z - 7 for c in terms of z.

1\(\frac{1}{2}\)z - \(\frac{1}{2}\)
\(\frac{2}{3}\)z - 2\(\frac{1}{3}\)
-2\(\frac{1}{7}\)z - \(\frac{4}{7}\)
2z - 3\(\frac{1}{2}\)