When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6a + 3a = -2a + x + 2 for a in terms of x.
| -\(\frac{1}{5}\)x - 1\(\frac{2}{5}\) | |
| -\(\frac{1}{4}\)x + \(\frac{1}{4}\) | |
| 2\(\frac{3}{4}\)x - \(\frac{3}{4}\) | |
| -1\(\frac{1}{4}\)x - \(\frac{3}{4}\) |