When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 6c = -5c - 2z + 8 for c in terms of z.
| -z + 3\(\frac{1}{2}\) | |
| 5z - 1 | |
| 2\(\frac{2}{3}\)z - 2\(\frac{2}{3}\) | |
| 4z + 1\(\frac{1}{4}\) |