ASVAB Math Knowledge Practice Test 678509 Results

Your Results Global Average
Questions 5 5
Correct 0 3.25
Score 0% 65%

Review

1

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the perimeter is the sum of the lengths of all four sides

all interior angles are right angles

the area is length x width

the lengths of all sides are equal


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

Simplify 2a x 8b.

86% Answer Correctly
16ab
16\( \frac{a}{b} \)
10ab
16\( \frac{b}{a} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

2a x 8b = (2 x 8) (a x b) = 16ab


3

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

squaring

factoring

normalizing

deconstructing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


4

Factor y2 + 5y - 36

54% Answer Correctly
(y - 4)(y - 9)
(y + 4)(y + 9)
(y + 4)(y - 9)
(y - 4)(y + 9)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -36 as well and sum (Inside, Outside) to equal 5. For this problem, those two numbers are -4 and 9. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 5y - 36
y2 + (-4 + 9)y + (-4 x 9)
(y - 4)(y + 9)


5

The endpoints of this line segment are at (-2, 1) and (2, 3). What is the slope of this line?

46% Answer Correctly
3
2
1
\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, 3) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(3.0) - (1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)