When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 8c = -5c - 7x - 5 for c in terms of x.
| -1\(\frac{2}{3}\)x - \(\frac{5}{9}\) | |
| \(\frac{5}{8}\)x + 1 | |
| \(\frac{3}{5}\)x - 1\(\frac{3}{5}\) | |
| 1\(\frac{5}{6}\)x - \(\frac{2}{3}\) |