When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + c = 2c + 3x + 1 for c in terms of x.
| \(\frac{1}{2}\)x + \(\frac{1}{4}\) | |
| -\(\frac{1}{6}\)x + \(\frac{1}{6}\) | |
| x + \(\frac{4}{13}\) | |
| 6\(\frac{1}{2}\)x - 2\(\frac{1}{2}\) |