ASVAB Math Knowledge Practice Test 679552

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - a = 7a + 6y - 3 for a in terms of y.

\(\frac{1}{5}\)y - 1
\(\frac{1}{2}\)y + \(\frac{1}{4}\)
-2\(\frac{1}{3}\)y + 1
\(\frac{1}{5}\)y - \(\frac{2}{5}\)