When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 4c = c - 9z + 6 for c in terms of z.
| 15z - 7 | |
| \(\frac{5}{9}\)z - 1 | |
| -1\(\frac{6}{7}\)z + \(\frac{6}{7}\) | |
| 3z + 1 |