ASVAB Math Knowledge Practice Test 680127

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5a - 3a = 4a + 5y + 1 for a in terms of y.

y + 2
8y + 1
10y + 2
\(\frac{1}{2}\)y - 3\(\frac{1}{2}\)