When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 5c = 3c + z + 3 for c in terms of z.
| 6z + 3 | |
| -1\(\frac{1}{5}\)z - 1\(\frac{4}{5}\) | |
| -z - \(\frac{1}{3}\) | |
| -\(\frac{5}{13}\)z + \(\frac{7}{13}\) |