ASVAB Math Knowledge Practice Test 684858

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a + 2a = -9a + 9z + 5 for a in terms of z.

-5z - 9
\(\frac{4}{5}\)z - \(\frac{1}{5}\)
3z - \(\frac{1}{2}\)
\(\frac{7}{15}\)z + \(\frac{1}{3}\)