When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 5c = -9c + 6z - 3 for c in terms of z.
| \(\frac{1}{3}\)z - \(\frac{8}{15}\) | |
| 2z + 3 | |
| \(\frac{1}{11}\)z - \(\frac{3}{11}\) | |
| -4z - 3 |