| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.78 |
| Score | 0% | 56% |
The formula for the area of a circle is which of the following?
a = π d |
|
a = π r |
|
a = π d2 |
|
a = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Find the value of b:
8b + x = -4
-b + x = 2
| -\(\frac{2}{3}\) | |
| 1\(\frac{19}{29}\) | |
| \(\frac{11}{31}\) | |
| -4\(\frac{3}{7}\) |
You need to find the value of b so solve the first equation in terms of x:
8b + x = -4
x = -4 - 8b
then substitute the result (-4 - 8b) into the second equation:
-b + 1(-4 - 8b) = 2
-b + (1 x -4) + (1 x -8b) = 2
-b - 4 - 8b = 2
-b - 8b = 2 + 4
-9b = 6
b = \( \frac{6}{-9} \)
b = -\(\frac{2}{3}\)
Solve 7b + 4b = -7b + 6z + 1 for b in terms of z.
| 4z + 7 | |
| \(\frac{1}{7}\)z + \(\frac{1}{14}\) | |
| -2\(\frac{2}{3}\)z + \(\frac{1}{3}\) | |
| 2\(\frac{1}{5}\)z - 1\(\frac{2}{5}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
7b + 4z = -7b + 6z + 1
7b = -7b + 6z + 1 - 4z
7b + 7b = 6z + 1 - 4z
14b = 2z + 1
b = \( \frac{2z + 1}{14} \)
b = \( \frac{2z}{14} \) + \( \frac{1}{14} \)
b = \(\frac{1}{7}\)z + \(\frac{1}{14}\)
If the length of AB equals the length of BD, point B __________ this line segment.
trisects |
|
midpoints |
|
bisects |
|
intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
If a = c = 4, b = d = 5, what is the area of this rectangle?
| 54 | |
| 20 | |
| 8 | |
| 42 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 4 x 5
a = 20