| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
If the base of this triangle is 9 and the height is 9, what is the area?
| 45 | |
| 52\(\frac{1}{2}\) | |
| 65 | |
| 40\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 9 = \( \frac{81}{2} \) = 40\(\frac{1}{2}\)
Solve for y:
y2 - 16y + 64 = 0
| 9 or -7 | |
| 6 or -2 | |
| -6 or -9 | |
| 8 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
y2 - 16y + 64 = 0
(y - 8)(y - 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, (y - 8) must equal zero:
If (y - 8) = 0, y must equal 8
So the solution is that y = 8
The dimensions of this cube are height (h) = 7, length (l) = 6, and width (w) = 8. What is the volume?
| 336 | |
| 189 | |
| 6 | |
| 32 |
The volume of a cube is height x length x width:
v = h x l x w
v = 7 x 6 x 8
v = 336
If a = c = 1, b = d = 9, and the blue angle = 54°, what is the area of this parallelogram?
| 7 | |
| 16 | |
| 9 | |
| 4 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 1 x 9
a = 9
Solve for a:
a2 + 2a - 41 = 2a - 5
| 7 or -1 | |
| 3 or 2 | |
| 3 or -6 | |
| 6 or -6 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
a2 + 2a - 41 = 2a - 5
a2 + 2a - 41 + 5 = 2a
a2 + 2a - 2a - 36 = 0
a2 - 36 = 0
Next, factor the quadratic equation:
a2 - 36 = 0
(a - 6)(a + 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 6) or (a + 6) must equal zero:
If (a - 6) = 0, a must equal 6
If (a + 6) = 0, a must equal -6
So the solution is that a = 6 or -6