| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.63 |
| Score | 0% | 53% |
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
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trisects |
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midpoints |
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bisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
The dimensions of this cube are height (h) = 2, length (l) = 8, and width (w) = 5. What is the surface area?
| 94 | |
| 62 | |
| 132 | |
| 102 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 8 x 5) + (2 x 5 x 2) + (2 x 8 x 2)
sa = (80) + (20) + (32)
sa = 132
Factor y2 - 14y + 48
| (y - 8)(y + 6) | |
| (y + 8)(y - 6) | |
| (y - 8)(y - 6) | |
| (y + 8)(y + 6) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 48 as well and sum (Inside, Outside) to equal -14. For this problem, those two numbers are -8 and -6. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 14y + 48
y2 + (-8 - 6)y + (-8 x -6)
(y - 8)(y - 6)
If angle a = 21° and angle b = 41° what is the length of angle c?
| 60° | |
| 88° | |
| 47° | |
| 118° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 21° - 41° = 118°
Find the value of a:
-3a + x = -2
2a + x = -2
| -\(\frac{13}{17}\) | |
| 1 | |
| -\(\frac{1}{2}\) | |
You need to find the value of a so solve the first equation in terms of x:
-3a + x = -2
x = -2 + 3a
then substitute the result (-2 - -3a) into the second equation:
2a + 1(-2 + 3a) = -2
2a + (1 x -2) + (1 x 3a) = -2
2a - 2 + 3a = -2
2a + 3a = -2 + 2
5a = 0
a = \( \frac{0}{5} \)
a =