| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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a2 - c2 |
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c - a |
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c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If the area of this square is 64, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 8\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)
Which of the following expressions contains exactly two terms?
binomial |
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polynomial |
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monomial |
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quadratic |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
Which of the following is not true about both rectangles and squares?
the lengths of all sides are equal |
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the perimeter is the sum of the lengths of all four sides |
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the area is length x width |
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all interior angles are right angles |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
The endpoints of this line segment are at (-2, 7) and (2, -1). What is the slope of this line?
| -2 | |
| 3 | |
| 1\(\frac{1}{2}\) | |
| 2 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 7) and (2, -1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (7.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)