When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b - 5b = 9b - 5z + 2 for b in terms of z.
| z - \(\frac{2}{3}\) | |
| -\(\frac{7}{12}\)z - \(\frac{2}{3}\) | |
| -\(\frac{2}{3}\)z + \(\frac{2}{3}\) | |
| \(\frac{1}{3}\)z - \(\frac{1}{5}\) |