| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
Which types of triangles will always have at least two sides of equal length?
isosceles and right |
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equilateral, isosceles and right |
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equilateral and isosceles |
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equilateral and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Solve for y:
y2 + 6y + 9 = 0
| -3 | |
| 8 or -6 | |
| 8 or -8 | |
| 5 or 4 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
y2 + 6y + 9 = 0
(y + 3)(y + 3) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, (y + 3) must equal zero:
If (y + 3) = 0, y must equal -3
So the solution is that y = -3
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
lw x wh + lh |
|
h2 x l2 x w2 |
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2lw x 2wh + 2lh |
|
h x l x w |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
Solve a - 6a = -7a - z - 3 for a in terms of z.
| 3\(\frac{1}{5}\)z - \(\frac{4}{5}\) | |
| \(\frac{5}{8}\)z - \(\frac{3}{8}\) | |
| -3\(\frac{2}{5}\)z - \(\frac{1}{5}\) | |
| 1\(\frac{2}{15}\)z - \(\frac{7}{15}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
a - 6z = -7a - z - 3
a = -7a - z - 3 + 6z
a + 7a = -z - 3 + 6z
8a = 5z - 3
a = \( \frac{5z - 3}{8} \)
a = \( \frac{5z}{8} \) + \( \frac{-3}{8} \)
a = \(\frac{5}{8}\)z - \(\frac{3}{8}\)
Solve for z:
-8z - 6 = -4 + 9z
| -\(\frac{2}{3}\) | |
| -\(\frac{2}{17}\) | |
| -\(\frac{2}{9}\) | |
| -6 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-8z - 6 = -4 + 9z
-8z = -4 + 9z + 6
-8z - 9z = -4 + 6
-17z = 2
z = \( \frac{2}{-17} \)
z = -\(\frac{2}{17}\)