ASVAB Math Knowledge Practice Test 695068 Results

Your Results Global Average
Questions 5 5
Correct 0 2.66
Score 0% 53%

Review

1

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

trisects

bisects

midpoints

intersects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


2

The dimensions of this trapezoid are a = 6, b = 5, c = 9, d = 8, and h = 5. What is the area?

50% Answer Correctly
5
32\(\frac{1}{2}\)
34
16\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(5 + 8)(5)
a = ½(13)(5)
a = ½(65) = \( \frac{65}{2} \)
a = 32\(\frac{1}{2}\)


3

Simplify (7a)(9ab) - (7a2)(3b).

62% Answer Correctly
84a2b
-42ab2
84ab2
42a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(7a)(9ab) - (7a2)(3b)
(7 x 9)(a x a x b) - (7 x 3)(a2 x b)
(63)(a1+1 x b) - (21)(a2b)
63a2b - 21a2b
42a2b


4

On this circle, line segment CD is the:

46% Answer Correctly

chord

radius

circumference

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Simplify (y + 4)(y - 7)

63% Answer Correctly
y2 + 11y + 28
y2 - 3y - 28
y2 - 11y + 28
y2 + 3y - 28

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 4)(y - 7)
(y x y) + (y x -7) + (4 x y) + (4 x -7)
y2 - 7y + 4y - 28
y2 - 3y - 28