ASVAB Math Knowledge Practice Test 695109 Results

Your Results Global Average
Questions 5 5
Correct 0 3.09
Score 0% 62%

Review

1

If the base of this triangle is 1 and the height is 5, what is the area?

58% Answer Correctly
2\(\frac{1}{2}\)
27
78
52\(\frac{1}{2}\)

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 1 x 5 = \( \frac{5}{2} \) = 2\(\frac{1}{2}\)


2

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

4π r2

π r2h2

π r2h

2(π r2) + 2π rh


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


3

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

vertical, supplementary

supplementary, vertical

acute, obtuse

obtuse, acute


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


4

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
8\( \sqrt{2} \)
3\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)


5

What is the circumference of a circle with a diameter of 14?

70% Answer Correctly
28π
1π
14π
10π

Solution

The formula for circumference is circle diameter x π:

c = πd
c = 14π