When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 6c = c - 2z - 5 for c in terms of z.
| -1\(\frac{1}{4}\)z - 1 | |
| 1\(\frac{1}{3}\)z + \(\frac{5}{6}\) | |
| -z - 5 | |
| \(\frac{4}{17}\)z + \(\frac{7}{17}\) |