To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

3a x 3b = (3 x 3) (a x b) = 9ab

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

3c - 7 < \( \frac{c}{-2} \)
-2 x (3c - 7) < c
(-2 x 3c) + (-2 x -7) < c
-6c + 14 < c
-6c + 14 - c < 0
-6c - c < -14
-7c < -14
c < \( \frac{-14}{-7} \)
c < 2

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 6 x 9 = \( \frac{54}{2} \) = 27

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c² - 6c + 5 = 0
(c - 1)(c - 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 1) or (c - 5) must equal zero:

If (c - 1) = 0, c must equal 1
If (c - 5) = 0, c must equal 5

So the solution is that c = 1 or 5