ASVAB Math Knowledge Practice Test 697709 Results

Your Results Global Average
Questions 5 5
Correct 0 2.62
Score 0% 52%

Review

1

Solve for b:
b2 + 7b - 18 = 0

57% Answer Correctly
4 or -9
9 or 3
6 or -4
2 or -9

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

b2 + 7b - 18 = 0
(b - 2)(b + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 2) or (b + 9) must equal zero:

If (b - 2) = 0, b must equal 2
If (b + 9) = 0, b must equal -9

So the solution is that b = 2 or -9


2

The dimensions of this cylinder are height (h) = 7 and radius (r) = 1. What is the surface area?

48% Answer Correctly
140π
56π
16π
80π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 7)
sa = 2π(1) + 2π(7)
sa = (2 x 1)π + (2 x 7)π
sa = 2π + 14π
sa = 16π


3

What is the area of a circle with a radius of 4?

69% Answer Correctly
16π
4π
3π
25π

Solution

The formula for area is πr2:

a = πr2
a = π(42)
a = 16π


4

Solve -9a - 4a = -3a + 5y + 2 for a in terms of y.

34% Answer Correctly
-5y + 3\(\frac{1}{2}\)
\(\frac{9}{13}\)y - \(\frac{8}{13}\)
-1\(\frac{1}{4}\)y - \(\frac{1}{4}\)
-1\(\frac{1}{2}\)y - \(\frac{1}{3}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-9a - 4y = -3a + 5y + 2
-9a = -3a + 5y + 2 + 4y
-9a + 3a = 5y + 2 + 4y
-6a = 9y + 2
a = \( \frac{9y + 2}{-6} \)
a = \( \frac{9y}{-6} \) + \( \frac{2}{-6} \)
a = -1\(\frac{1}{2}\)y - \(\frac{1}{3}\)


5

Which types of triangles will always have at least two sides of equal length?

53% Answer Correctly

equilateral and isosceles

equilateral, isosceles and right

equilateral and right

isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.