| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.62 |
| Score | 0% | 52% |
Solve for b:
b2 + 7b - 18 = 0
| 4 or -9 | |
| 9 or 3 | |
| 6 or -4 | |
| 2 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
b2 + 7b - 18 = 0
(b - 2)(b + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 2) or (b + 9) must equal zero:
If (b - 2) = 0, b must equal 2
If (b + 9) = 0, b must equal -9
So the solution is that b = 2 or -9
The dimensions of this cylinder are height (h) = 7 and radius (r) = 1. What is the surface area?
| 140π | |
| 56π | |
| 16π | |
| 80π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 7)
sa = 2π(1) + 2π(7)
sa = (2 x 1)π + (2 x 7)π
sa = 2π + 14π
sa = 16π
What is the area of a circle with a radius of 4?
| 16π | |
| 4π | |
| 3π | |
| 25π |
The formula for area is πr2:
a = πr2
a = π(42)
a = 16π
Solve -9a - 4a = -3a + 5y + 2 for a in terms of y.
| -5y + 3\(\frac{1}{2}\) | |
| \(\frac{9}{13}\)y - \(\frac{8}{13}\) | |
| -1\(\frac{1}{4}\)y - \(\frac{1}{4}\) | |
| -1\(\frac{1}{2}\)y - \(\frac{1}{3}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-9a - 4y = -3a + 5y + 2
-9a = -3a + 5y + 2 + 4y
-9a + 3a = 5y + 2 + 4y
-6a = 9y + 2
a = \( \frac{9y + 2}{-6} \)
a = \( \frac{9y}{-6} \) + \( \frac{2}{-6} \)
a = -1\(\frac{1}{2}\)y - \(\frac{1}{3}\)
Which types of triangles will always have at least two sides of equal length?
equilateral and isosceles |
|
equilateral, isosceles and right |
|
equilateral and right |
|
isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.