| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.68 |
| Score | 0% | 54% |
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
4π r2 |
|
π r2h2 |
|
2(π r2) + 2π rh |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
The dimensions of this cylinder are height (h) = 2 and radius (r) = 4. What is the volume?
| 48π | |
| 50π | |
| 32π | |
| 180π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(42 x 2)
v = 32π
Solve for y:
2y - 7 = 2 - 8y
| -\(\frac{1}{3}\) | |
| \(\frac{9}{10}\) | |
| -\(\frac{4}{7}\) | |
| \(\frac{4}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
2y - 7 = 2 - 8y
2y = 2 - 8y + 7
2y + 8y = 2 + 7
10y = 9
y = \( \frac{9}{10} \)
y = \(\frac{9}{10}\)
The dimensions of this trapezoid are a = 5, b = 9, c = 8, d = 8, and h = 4. What is the area?
| 24 | |
| 7\(\frac{1}{2}\) | |
| 22 | |
| 34 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(9 + 8)(4)
a = ½(17)(4)
a = ½(68) = \( \frac{68}{2} \)
a = 34
Find the value of b:
5b + x = 2
6b - 7x = 3
| -1\(\frac{2}{5}\) | |
| 7 | |
| \(\frac{17}{41}\) | |
| 14\(\frac{3}{4}\) |
You need to find the value of b so solve the first equation in terms of x:
5b + x = 2
x = 2 - 5b
then substitute the result (2 - 5b) into the second equation:
6b - 7(2 - 5b) = 3
6b + (-7 x 2) + (-7 x -5b) = 3
6b - 14 + 35b = 3
6b + 35b = 3 + 14
41b = 17
b = \( \frac{17}{41} \)
b = \(\frac{17}{41}\)