ASVAB Math Knowledge Practice Test 701321 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

Simplify (y + 6)(y + 2)

62% Answer Correctly
y2 + 4y - 12
y2 - 4y - 12
y2 + 8y + 12
y2 - 8y + 12

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 6)(y + 2)
(y x y) + (y x 2) + (6 x y) + (6 x 2)
y2 + 2y + 6y + 12
y2 + 8y + 12


2

A right angle measures:

89% Answer Correctly

90°

360°

45°

180°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


3

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
2\( \sqrt{2} \)
8\( \sqrt{2} \)
\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)


4

If side a = 5, side b = 1, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{89} \)
\( \sqrt{26} \)
\( \sqrt{18} \)
\( \sqrt{106} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 52 + 12
c2 = 25 + 1
c2 = 26
c = \( \sqrt{26} \)


5

Solve for b:
-4b - 5 < \( \frac{b}{-5} \)

44% Answer Correctly
b < -1\(\frac{7}{9}\)
b < -\(\frac{6}{11}\)
b < \(\frac{7}{29}\)
b < -1\(\frac{6}{19}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-4b - 5 < \( \frac{b}{-5} \)
-5 x (-4b - 5) < b
(-5 x -4b) + (-5 x -5) < b
20b + 25 < b
20b + 25 - b < 0
20b - b < -25
19b < -25
b < \( \frac{-25}{19} \)
b < -1\(\frac{6}{19}\)