ASVAB Math Knowledge Practice Test 701475 Results

Your Results Global Average
Questions 5 5
Correct 0 2.72
Score 0% 54%

Review

1

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

c2 + a2

c - a

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


2

The dimensions of this cube are height (h) = 7, length (l) = 1, and width (w) = 1. What is the surface area?

51% Answer Correctly
202
82
30
270

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 1 x 1) + (2 x 1 x 7) + (2 x 1 x 7)
sa = (2) + (14) + (14)
sa = 30


3

Solve for x:
x2 + 4x + 3 = 0

58% Answer Correctly
-2 or -6
8 or 7
-1 or -3
-9 or -9

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

x2 + 4x + 3 = 0
(x + 1)(x + 3) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 1) or (x + 3) must equal zero:

If (x + 1) = 0, x must equal -1
If (x + 3) = 0, x must equal -3

So the solution is that x = -1 or -3


4

Simplify (8a)(7ab) + (4a2)(5b).

65% Answer Correctly
-36ab2
135a2b
76a2b
76ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(7ab) + (4a2)(5b)
(8 x 7)(a x a x b) + (4 x 5)(a2 x b)
(56)(a1+1 x b) + (20)(a2b)
56a2b + 20a2b
76a2b


5

The dimensions of this trapezoid are a = 6, b = 3, c = 9, d = 8, and h = 5. What is the area?

51% Answer Correctly
27\(\frac{1}{2}\)
15
18
16\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(3 + 8)(5)
a = ½(11)(5)
a = ½(55) = \( \frac{55}{2} \)
a = 27\(\frac{1}{2}\)