When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 9c = 6c + z - 4 for c in terms of z.
| \(\frac{5}{6}\)z + 1\(\frac{1}{3}\) | |
| \(\frac{12}{13}\)z - \(\frac{7}{13}\) | |
| -2\(\frac{1}{2}\)z - \(\frac{1}{2}\) | |
| -2\(\frac{2}{3}\)z - 1\(\frac{1}{3}\) |