| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.33 |
| Score | 0% | 67% |
Solve for y:
9y + 4 = 7 - 2y
| \(\frac{3}{11}\) | |
| -\(\frac{1}{3}\) | |
| 5 | |
| \(\frac{5}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
9y + 4 = 7 - 2y
9y = 7 - 2y - 4
9y + 2y = 7 - 4
11y = 3
y = \( \frac{3}{11} \)
y = \(\frac{3}{11}\)
If a = c = 8, b = d = 7, what is the area of this rectangle?
| 2 | |
| 35 | |
| 56 | |
| 32 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 8 x 7
a = 56
What is 5a9 + 4a9?
| 20a18 | |
| 9a9 | |
| a18 | |
| 20a9 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a9 + 4a9 = 9a9
Find the value of c:
6c + y = -9
4c - 7y = 1
| -6 | |
| -1\(\frac{8}{23}\) | |
| -3 | |
| -2\(\frac{1}{4}\) |
You need to find the value of c so solve the first equation in terms of y:
6c + y = -9
y = -9 - 6c
then substitute the result (-9 - 6c) into the second equation:
4c - 7(-9 - 6c) = 1
4c + (-7 x -9) + (-7 x -6c) = 1
4c + 63 + 42c = 1
4c + 42c = 1 - 63
46c = -62
c = \( \frac{-62}{46} \)
c = -1\(\frac{8}{23}\)
What is 6a3 - 7a3?
| -a6 | |
| 42a3 | |
| -1a3 | |
| 13 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
6a3 - 7a3 = -1a3