When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8b + 4b = -2b + 3y + 3 for b in terms of y.
| -\(\frac{1}{10}\)y + \(\frac{3}{10}\) | |
| -1\(\frac{1}{3}\)y + 1\(\frac{1}{6}\) | |
| \(\frac{7}{15}\)y - \(\frac{1}{5}\) | |
| \(\frac{13}{15}\)y - \(\frac{1}{3}\) |