The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 0. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, 3) so the slope becomes:

Plugging these values into the slope-intercept equation:

y = 1\(\frac{1}{2}\)x + 0

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a² - 10a + 14 = -a - 4
a² - 10a + 14 + 4 = -a
a² - 10a + a + 18 = 0
a² - 9a + 18 = 0

Next, factor the quadratic equation:

a² - 9a + 18 = 0
(a - 3)(a - 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 3) or (a - 6) must equal zero:

If (a - 3) = 0, a must equal 3
If (a - 6) = 0, a must equal 6

So the solution is that a = 3 or 6

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

x² + x - 56 = 0
(x - 7)(x + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (x - 7) or (x + 8) must equal zero:

If (x - 7) = 0, x must equal 7
If (x + 8) = 0, x must equal -8

So the solution is that x = 7 or -8