| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.51 |
| Score | 0% | 70% |
Solve for z:
z2 + 11z + 24 = 0
| 3 or 1 | |
| -3 or -8 | |
| 4 or -2 | |
| -7 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 + 11z + 24 = 0
(z + 3)(z + 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 3) or (z + 8) must equal zero:
If (z + 3) = 0, z must equal -3
If (z + 8) = 0, z must equal -8
So the solution is that z = -3 or -8
Simplify (y - 5)(y - 1)
| y2 + 4y - 5 | |
| y2 - 6y + 5 | |
| y2 - 4y - 5 | |
| y2 + 6y + 5 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y - 5)(y - 1)
(y x y) + (y x -1) + (-5 x y) + (-5 x -1)
y2 - y - 5y + 5
y2 - 6y + 5
If c = 8 and x = 4, what is the value of 3c(c - x)?
| 96 | |
| -135 | |
| -360 | |
| -6 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
3c(c - x)
3(8)(8 - 4)
3(8)(4)
(24)(4)
96
If side x = 14cm, side y = 9cm, and side z = 7cm what is the perimeter of this triangle?
| 30cm | |
| 36cm | |
| 18cm | |
| 37cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 14cm + 9cm + 7cm = 30cm
What is 8a + 7a?
| 56a2 | |
| 1 | |
| 15a | |
| 56a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a + 7a = 15a