| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.47 |
| Score | 0% | 49% |
The dimensions of this cube are height (h) = 6, length (l) = 8, and width (w) = 9. What is the surface area?
| 28 | |
| 72 | |
| 348 | |
| 52 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 8 x 9) + (2 x 9 x 6) + (2 x 8 x 6)
sa = (144) + (108) + (96)
sa = 348
Solve for a:
9a - 3 = -4 - 8a
| -\(\frac{1}{5}\) | |
| -\(\frac{1}{7}\) | |
| -\(\frac{1}{17}\) | |
| -1 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
9a - 3 = -4 - 8a
9a = -4 - 8a + 3
9a + 8a = -4 + 3
17a = -1
a = \( \frac{-1}{17} \)
a = -\(\frac{1}{17}\)
If the base of this triangle is 5 and the height is 8, what is the area?
| 40 | |
| 58\(\frac{1}{2}\) | |
| 20 | |
| 33 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 5 x 8 = \( \frac{40}{2} \) = 20
On this circle, a line segment connecting point A to point D is called:
chord |
|
diameter |
|
radius |
|
circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve 8b + 9b = -5b - 4y + 3 for b in terms of y.
| -y + \(\frac{3}{13}\) | |
| \(\frac{5}{7}\)y + \(\frac{1}{7}\) | |
| 4\(\frac{1}{2}\)y - 1\(\frac{1}{2}\) | |
| -\(\frac{1}{5}\)y + \(\frac{4}{5}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
8b + 9y = -5b - 4y + 3
8b = -5b - 4y + 3 - 9y
8b + 5b = -4y + 3 - 9y
13b = -13y + 3
b = \( \frac{-13y + 3}{13} \)
b = \( \frac{-13y}{13} \) + \( \frac{3}{13} \)
b = -y + \(\frac{3}{13}\)