When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c + 3c = -8c + 4z - 6 for c in terms of z.
| \(\frac{1}{14}\)z - \(\frac{3}{14}\) | |
| 3\(\frac{1}{2}\)z + 1\(\frac{1}{4}\) | |
| -z + 6 | |
| z - \(\frac{1}{16}\) |