When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 6c = 7c - 2z + 4 for c in terms of z.
| \(\frac{4}{7}\)z + 1 | |
| -1\(\frac{1}{3}\)z - 1\(\frac{1}{2}\) | |
| 1\(\frac{3}{5}\)z - \(\frac{4}{5}\) | |
| \(\frac{3}{10}\)z + \(\frac{4}{5}\) |