ASVAB Math Knowledge Practice Test 706871 Results

Your Results Global Average
Questions 5 5
Correct 0 2.99
Score 0% 60%

Review

1

Simplify (7a)(8ab) + (7a2)(2b).

65% Answer Correctly
135ab2
70a2b
135a2b
-42a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(7a)(8ab) + (7a2)(2b)
(7 x 8)(a x a x b) + (7 x 2)(a2 x b)
(56)(a1+1 x b) + (14)(a2b)
56a2b + 14a2b
70a2b


2

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the area is length x width

the perimeter is the sum of the lengths of all four sides

all interior angles are right angles

the lengths of all sides are equal


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


3

If side x = 10cm, side y = 14cm, and side z = 5cm what is the perimeter of this triangle?

84% Answer Correctly
16cm
29cm
20cm
22cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 10cm + 14cm + 5cm = 29cm


4

Find the value of c:
6c + z = -1
8c + z = 8

42% Answer Correctly
-\(\frac{5}{13}\)
-\(\frac{1}{6}\)
4\(\frac{1}{2}\)
1\(\frac{5}{21}\)

Solution

You need to find the value of c so solve the first equation in terms of z:

6c + z = -1
z = -1 - 6c

then substitute the result (-1 - 6c) into the second equation:

8c + 1(-1 - 6c) = 8
8c + (1 x -1) + (1 x -6c) = 8
8c - 1 - 6c = 8
8c - 6c = 8 + 1
2c = 9
c = \( \frac{9}{2} \)
c = 4\(\frac{1}{2}\)


5

Solve for x:
7x - 6 = \( \frac{x}{-6} \)

46% Answer Correctly
-1\(\frac{13}{23}\)
-2\(\frac{2}{7}\)
\(\frac{36}{43}\)
-1\(\frac{1}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

7x - 6 = \( \frac{x}{-6} \)
-6 x (7x - 6) = x
(-6 x 7x) + (-6 x -6) = x
-42x + 36 = x
-42x + 36 - x = 0
-42x - x = -36
-43x = -36
x = \( \frac{-36}{-43} \)
x = \(\frac{36}{43}\)